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[linux_var] bash capitolo 2
- To: linux_var - LUG List <talking@ml.linuxvar.it>
- Subject: [linux_var] bash capitolo 2
- From: Cristian Gaiatto <g.crinux@gmail.com>
- Date: Mon, 15 Jul 2013 23:21:42 +0200
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Problemi con script bash seconda puntata.
prendo la 2 riga di un file che contiene il nome dell'immagine che
voglio aprire
riga_disegno=$(sed -n 2p $nomefile)
$nomefile è ricavato dalla parte precedente dello script
ottenuto il nome dell'immagine passo il comando per aprirla
xdg-open "/home/cristian/Immagini/$riga_disegno"
apre il programma per la visualizzazione delle immagini ma non l'immagine.
La variabile $riga_disegno è corretta (SM83162.jpg controllata con echo)
e se da terminale do' il comando
xdg-open "/home/cristian/Immagini/SM83162.jpg"
mi apre correttamente l'immagine.
Sbaglio qualche cosa?
Cristian
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